Can a Panoramic Padel Court Resist a Typhoon (Beaufort 10)?

Engineering Analysis & Practical Guidance for Court Buyers

Panoramic padel courts are admired for their stunning visibility and premium aesthetic-but because they remove the traditional vertical steel posts behind the glass, many buyers naturally ask:

"Can a panoramic padel court safely resist a typhoon-level wind (Beaufort 10, approx. 25–30 m/s)?"

In this article, we combine real engineering calculations with practical design guidance to answer the question clearly.
All data below is based on 12 mm tempered glass, Q235 steel, 100×100 mm corner posts, 100×50 mm upper/lower beams, 3 mm steel tube thickness, and a typical panoramic padel glass size of 1.995 m × 2.995 m.

1. Wind Speed → Wind Pressure Calculation

We use the standard dynamic pressure formula:

p=0.613 V2(V in m/s)p = 0.613\,V^2 \quad (V \text{ in m/s})p=0.613V2(V in m/s)

Example wind speeds

Calculate wind pressure

At 25 m/s:

p=0.613×252=383.1 N/m2p = 0.613 \times 25^2 = 383.1\ \text{N/m}^2p=0.613×252=383.1 N/m2

At 30 m/s:

p=0.613×302=551.7 N/m2p = 0.613 \times 30^2 = 551.7\ \text{N/m}^2p=0.613×302=551.7 N/m2

2. Wind Force on the Glass Panel

Glass panel area:

A=1.995×2.995=5.975 m2A = 1.995 \times 2.995 = 5.975\ \text{m}^2A=1.995×2.995=5.975 m2

Wind Force = Pressure × Area

At 25 m/s

F=383.1×5.975=2,289 N=2.289 kNF = 383.1 \times 5.975 = 2,289\ \text{N} = 2.289\ \text{kN}F=383.1×5.975=2,289 N=2.289 kN

At 30 m/s

F=551.7×5.975=3,296 N=3.296 kNF = 551.7 \times 5.975 = 3,296\ \text{N} = 3.296\ \text{kN}F=551.7×5.975=3,296 N=3.296 kN

Ultimate Design Force (safety factor 1.5)

These are horizontal forces acting on a single panoramic glass panel.

3. Can 12 mm Tempered Glass Resist This Wind Load?

Mechanical strength of 12 mm tempered glass:

149.1 N/mm2=149.1 MPa149.1\ \text{N/mm}^2 = 149.1\ \text{MPa}149.1 N/mm2=149.1 MPa

Even under 30 m/s wind:

Pressure = 551.7 N/m² = 0.0005517 N/mm²

This is over 250,000 times smaller than the breaking strength of tempered glass.

Conclusion (Glass):

12 mm tempered glass easily withstands Beaufort 10 wind.
Actual wind pressure is extremely small compared to the strength of the glass.

4. Steel Structure Strength Check

Panoramic steel structure (Q235):

Corner posts: 100×100×3 mm

Beams: 100×50×3 mm

Material yield strength:

fy=235 MPaf_y = 235\ \text{MPa}fy​=235 MPa

4.1 Structural Bending from Wind

Worst-case applied moment on the supporting beam/post (uniform pressure assumed):

M=F×H2M = F \times \frac{H}{2}M=F×2H​

For wind at 30 m/s:

M=3.296 kN×1.4975 m=4.93 kN\cdotpmM = 3.296\ \text{kN} \times 1.4975\ \text{m} = 4.93\ \text{kN·m}M=3.296 kN×1.4975 m=4.93 kN\cdotpm

This moment is very small relative to a 100×100×3 mm steel tube's capacity.

Section modulus of 100×100×3 tube:

Z=(bh3−(b−2t)(h−2t)3)6hZ = \frac{(b h^3 - (b-2t)(h-2t)^3)}{6h}Z=6h(bh3−(b−2t)(h−2t)3)​

For 100×100×3 mm:

Z≈55,100 mm3=5.51×10−5 m3Z \approx 55,100\ \text{mm}^3 = 5.51 \times 10^{-5}\ \text{m}^3Z≈55,100 mm3=5.51×10−5 m3

Bending stress:

σ=MZ=4.93×1035.51×10−5=89.4 MPa\sigma = \frac{M}{Z} = \frac{4.93 \times 10^3}{5.51 \times 10^{-5}} = 89.4\ \text{MPa}σ=ZM​=5.51×10−54.93×103​=89.4 MPa

Yield limit:

235 MPa235\ \text{MPa}235 MPa

Utilization:

89.4/235=38%89.4 / 235 = 38\%89.4/235=38%

Conclusion (Steel Structure):

The 100×100×3 mm Q235 post operates at only 38% of its strength under Beaufort 10 winds.
Strong safety margin.

5. Anchor Load Check

Ultimate horizontal force per panel at 30 m/s:

Fult=4.944 kNF_{ult} = 4.944\ \text{kN}Fult​=4.944 kN

If shared by 3 anchors at the base:

4.944/3=1.648 kN per anchor4.944 / 3 = 1.648\ \text{kN per anchor}4.944/3=1.648 kN per anchor

Given typical M10/M12 chemical anchors have 8–12 kN shear capacity, anchor safety is excellent.

6. Final Verdict: Can It Resist Beaufort 10?

Based on the full calculations:

Glass Safety

✔ 12 mm tempered glass wind pressure << glass strength
(pressure is 0.00055 MPa vs strength 149 MPa)

Steel Structure Safety (Q235)

✔ 100×100×3 steel post stress = only 38% of yield
✔ 100×50×3 beam is even stronger relative to load

Anchors

✔ Required per-anchor shear ≈ 1.6 kN
✔ Typical anchors provide 8–12 kN capacity

✅ **Conclusion:

A properly designed panoramic padel court CAN safely resist a Beaufort 10 typhoon (25–30 m/s).**

The padel courts supplied by Qingdao Migo Glass Co., Ltd- with 12 mm tempered glass, Q235 steel 100×100 mm posts, 100×50 mm beams, 3 mm tube thickness, and standard anchors - have more than enough safety margin for strong storms.

For higher wind regions (>40–50 m/s), upgrading to laminated glass + reinforced steel + denser anchor layout is recommended.

Contact Us

If you need wind-load calculation, technical advice, or quotations:

📧 Email: bella@migoglass.com
📞 WhatsApp / Phone: +86 18561397391
🌐 Website: www.migocourtglass.com

Our engineering team will help you choose the safest and most durable configuration for your project - whether it's a coastal resort, rooftop gym or sports center.